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4B • Escap® Ironless Rotor DC Micromotors and Step Motors
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6.2  Escap® Micromotor Energy Flow and Conversion

image

6.3  Development of the Equivalent Circuit


image

    Vo = applied terminal voltage
    Lm = rotor inductance
    Rm = rotor resistance
    Ei = motor's induced back Emf
    i = circuit current flow Summation of loop voltage drops yields:
    image


Since the Escap® rotor inductance is 100 to 1,000 times less than that of conventional "iron-core" motors it can be neglected. Therefore, the Lmformul term vanishes and the simplified voltage loop equation becomes:
      Vo = Rm i + Ei 

6.4 Fundamental Equations of the Ironless Rotor Motor 

6.4.1 Motor Model 
        formul

Since V = Rl + E we can substitute Kvω for E since the back emf is equal to the angular velocity (ω) multiplied by the motor constant (K).
   Where Kv is the back emf constant and KM is the torque constant. 
    thereforeV = Rl + Kvω and M = KMl.

NOTE: Kv = KM = K 

This equality exists only when Kv and KM are expressed in metric units.

NOTE:
Kv = formula  
           formula
Therefore:
      V = Rl + K ω   
      where K Kv = KM  

This same equation can be derived in another way as follows:
  Air gap power in = air gap power out
(from Figure 9)
       El = Mω 
    Kωl = Mω
   thereforeKl = M or l = image
Power ln = dissipation + power out.
(from Figure 10)
       Vl = l²R + El 
       Vl = l²R + Mω  
       Vl = l²R + Klω  
   thereforeV = lR + Kω 
Alternate Forms:
image

6.4.2 Torque Speed
formula


The complete torque expression including mechanical losses is:
  M = ML + Mf 
∴ML = M - Mf
Mf = Friction Torque
ML = Load Torque
M = Motor Torque
NOTE: the origin of the torque speed characteristic (Figure 12) is shifted to (Mf, lNL).
At no load current (lNL) the no load speed (w0) is:
   
at a particular load (ML) the corresponding speed (w) is:
   
In actual applications
     Mf << ML and lNL0
where w0 = (neglecting Mf)
therefore w = w0 - ML 
By definition stall torque is computed by: MSTALL =    
6.4.3 Power




By definition: POUT = MLω (Mechanical Power)
   img
at peak power:
     img

NOTE: Maximum mechanical power out cannot exceed 1/4 the stalled power input.

6.4.4 Efficiency

By definition: η = img
      POUT = MLω 

img

Where lL = load current
             lS = stall current
             lNL = no load current


Now PlN = VlL        but V = lS
     thereforePlN = lSlL R
 
     img
Solving for lL:
      img
Substituting in efficiency equation:
     img
6.4.5 Thermal Considerations



There is actually only one major criteria that should be taken into account when selecting an ironless rotor DC motor. The final armature temperature must not exceed its maximum rated value so that no separation in the winding occurs under high centrifugal force.
   Given this consideration, it is evident that the ambient temperature (θ0), the two thermal resistances (Rth1 = rotor to case; Rth2 = case to ambient), and the average power dissipation (Pd), have to be very precisely evaluated in a given application.

         Pd = l²R  (Watts)

         Δθ = Pd(RTh1 + RTh2) (ºC)

     Where RTh1 & RTh2 are (ºC/Watt)

The equation for the final armature (rotor) temperature is:

        θf = θ0 + Δ θ

      thereforeθf = θ0 + (RTh1 + RTh2)Pd ºC 

The change in rotor resistance with temperature is expressed as:

        Rf = R[1 + (.004)(θf - 20)]

where "R" is that rotor resistance at 20ºC and .004 is the coefficient of thermal resistance for copper at 20ºC, in OHMS/ºC.



Rf is the new resistance at temperature θf.
The maximum continuous average current is limited by the following thermal consideration:

    θMAX - θ0 = Δ θ = (RTH1 + RTH2) RfMAX 

    formula
Where θMAX is the maximum permissible rotor temperature (ie 100ºC for a standard motor). The increase in rotor temperature θ versus time with a constant dissipated power is:
  
 
where:    t is elapsed time in seconds
                τ1 is thermal time constant of coil (seconds).
                τ2 is thermal time constant of tube (seconds).

6.4.6 Dynamic Performance

6.4.6.1 Starting under load conditions can be expressed as follows:
   
substituting:


The solution for ω(0) = 0 is:
(see figure 14)
Where   
but (mechanical time constant of motor from catalog) 
 

NOTE: Speed of rotation h (RPM):
    
6.4.6.2 Starting an unloaded motor can be stated as follows:

      Where: ML = 0 and JL = 0  
                   τ = τM and ω = ω0  
                  
This means that after infinite time the unloaded motor (assume zero friction torque Mf) will attain the no-load angular velocity corresponding to the power supply voltage. Thus:
   
and ω0 = ω under these no load conditions.

For an unloaded motor the initial acceleration would be:
    img
Where:    Md = motor starting torque
                 JM = rotor inertia
                 ld = current corresponding to the starting torque

Integration of the function ω(t) with initial conditions of Φ (t = 0) = 0:
   img
    Φ (t = 0) = 0
  thereforeωτ + c = 0 or c = - ωτ 
  img
this new function is graphed in figure 15.

img

7.0 GEARBOXES APPLIED WITH ESCAP® MOTORS

where g = gear ratio
           
7.1 Efficiency: PlN = Mω 
                      
                    therforePOUT = ηPlN  

NOTE: Efficiency will change with temperature due to factors such as lubrication, gear mesh, etc.

7.2 Stall Rating of Gearbox:

      MSTALL = gηM          where MSTALL is motor stall torque

       
    This torque (M) must never be permitted to exceed the maximum stall torque rating of the gearbox as stated In the catalog.
    Expressed as a motor current limit:
   
7.3 Inertia Transfer

Acceleration of the load JL is expressed as:


Where:
ig
(JLM) is the load inertia referred to the motor shaft


page 4 - Considerations for the Control of DC Micromotors

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